1.47 understand an
electric current as a flow of electrons or ions
Current is basically a flow of charged particles and in a metal
wire, it is a flow of electrons. These have a negative 1 charge. Ions are
charged particles too as they have lost or gained electrons. The movements of
these ions are responsible for the conduction of electricity.
1.48 understand why covalent compounds do not conduct electricity
Covalent compounds do not
have spare free electrons that can move and carry the charge; and neither do
they contain ions-it’s a covalent compound
not an ionic compound.
1.49 understand why ionic compounds conduct electricity only when
molten or in solution
When they are a solid the
ions are not free to move and carry the charge. When they are molten-as in it
is in melted form-the ions are free to move. Remember in liquids the particles
are able to slide over each other and move whereas in solids the particles can
only vibrate around a fixed position. When the ionic compound is dissolved in a
solvent to form a solution the ions are also made free to move.
1.50 describe simple experiments to distinguish between
electrolytes and non-electrolytes
1.51 recall that electrolysis involves the formation of new
substances when ionic compounds conduct electricity
Passing an electric current through a compound which is either
molten or in solution causes chemical changes, the chemical reactions produce new
products—new substances.
1.52 describe simple experiments for the electrolysis, using inert
electrodes, of molten salts such as lead (II) bromide
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Right hand electrode: Cathode-attracts cations-is the negative electrode, as it is attracting positive ions.
Left hand electrode: Anode-attracts anions-is the positive electrode, as it is attracting negative ions.
[Opposite charges attract]
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Nothing happens until the lead (II) bromide melts.
Lead (II) bromide is an
ionic compound. The solid consists of a giant structure of lead (II) ions and
bromide ions packed regularly in a crystal lattice. It doesn’t have any mobile
electrons, and the ions are locked tightly in the lattice and aren’t free to
move. The solid lead (II) bromide doesn’t conduct electricity.
As soon as the solid
melts, the ions do become free to move around, and it is this movement that
enables the electrons to flow in the external circuit.
Electrodes are made out of
carbon-which is inert (unreactive).
As soon as you connect the
power source, it pumps any mobile electrons away from the left-hand electrode
towards the right-hand one. The excess of electrons in the right-hand electrode
makes it negatively charged-called the cathode. The left-hand electrode is
positively charged because it is short of electrons. There is a limit to how
many electrons can squeeze into the negative electrode (Cathode) because of the
repulsion by the electrons already there.
The positive lead (II)
ions are attracted to the cathode, which is the negative electrode. When they
get there, they gain 2 electrons each from the electrode and forms neutral lead
atoms. These fall to the bottom of the container as molten lead.
Pb2+ (l) + 2e-
à Pb (l)
This leaves spaces in the
cathode that more electrons can move into. The power source pumps new electrons
along the wire to fill those spaces.
Bromide ions are attracted
to the positive anode. When they get there, the extra electron which makes the
bromide ion negatively charged moves onto the anode because this electrode is
short of electrons.
The loss of the extra
electron turns each bromide ion into a bromine atom. These join in pairs (bond
covalently) to form bromine molecules. Overall:
2Br-(l) à Br2
(g) + 2e-
The new electrons on the
anode are pumped away by the power source to help fill the spaces being created
at the cathode.
The ions are discharged at the electrodes.
Discharging an ion simply means that it loses its charge-either giving up
electron(s) to the electrode or receiving electron(s) from it.
Redox reaction
Look back at the ionic
equations, see that the lead (II) ions gain electrons at the cathode. Gain of
electrons is reduction. The lead (II) ions are reduced to lead atoms.
The bromide ions lose
electrons at the anode. Loss of electrons is oxidation. The bromide ions are oxidized
to bromine molecules.
1.54 write ionic half-equations representing the reactions at the
electrodes during electrolysis
For the electrolysis of lead (II) bromide, PbBr2
Cathode:
Pb2+ (l) + 2e-
à Pb (l)
Anode:
2Br-(l) à Br2
(g) + 2e-

SO HELPFULLLLLL THANKS
ReplyDeleteThanks:)
ReplyDeletei still get confused\:
ReplyDeletethanks :)
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ReplyDeletethanks you really helped me understand electrolysis
ReplyDeleteThis was a really helpful and interesting way to recap!
ReplyDeleteThanks soo much....you are doing a great job!
The questions are really helpful
ReplyDeletei have exams coming up and this was a great recap since i never understood what my teachers explained :zzzzzzz
ReplyDelete=))