## Tuesday, 3 April 2012

### Mole calculations

Updated, as of 06.04.13, with ANSWERS to any qs at the bottom of the post. Don't go straight to them! Try doing the qs first. :)

For whoever asked for mole calculations. :)
It's detailed and has some example questions with working out, and some practice questions and tables for you to do too. Hope it helps!
Note that these are taken from my class book. They are not my materials.

1.15 calculate relative formula masses (Mr) from relative atomic masses (Ar)

Relative formula mass: the sum of masses of all the atoms in a formula
Relative atomic mass: the average mass of all the isotopes of an element

Examples:
 Species Formula No. of atoms of each element in one molecule Ar of each element Sum of Ar Relative Formula Mass (Mr) Carbon dioxide CO2 1 carbon 2 oxygen C=12 O=16 12 + (16 x 2) 44 Oxygen O2 2 oxygen O=16 16 x 2 32 Aluminium oxide Al2O3 2 aluminium 3 oxygen Al=27 O=16 (27 x 2) + (16 x 3) 102 Aluminium sulphate Al2(SO4)3 2 aluminium 3 sulphur 12 oxygen Al=27 S=32 O=16 (27 x 2) + (32 x 3) + (16 x 12) 342

To calculate relative atomic mass (Ar): the sum of the relative abundance of each isotope multiplied by its mass number, divided by 100.

E.g. About 75% of all chlorine atoms have a mass number of 35 (18 neutrons), about 25% have a mass number of 37 (20 neutrons).

The relative atomic mass of chlorine is:
(75 x 35) + (25 x 37) / 100 = 35.5

1.18 carry out mole calculations using relative atomic mass (Ar) and relative formula mass (Mr)

n=m/Mr
Where n=number of moles, m=mass in grams and Mr=relative formula mass

e.g. how many moles are there in 120g of NaOH(s)?
n=m/Mr = 120g/40 = 3
There are 3 moles.

Try filling this out:

 Substance Formula Mr Mass of sample (g) Number of moles in sample (n=m/Mr) E.g. Water H2O 18 9 0.5 Carbon dioxide 88 Ammonia 1.7 Sulphur dioxide 0.64 Sulphur trioxide 80 Hydrogen bromide 24.3 Sulphuric acid 0.098 Nitric acid 3.15 Sodium nitrate 21.25 Sodium carbonate 53

Example:
What mass of hydrogen is produced when 192g of magnesium is reacted with hydrochloric acid?

Step 1: write a balanced equation for the reaction:
Mg + 2HCl à MgCl2 + H2

Step 2: under the equation, fill in all the information you have been given, and also the Mr of the species involved:

 Equation Mg                  +                 2HCl                     à          MgCl2                      +                H2 Mass 192g This is the value you want to find Mr 24 2 n

Step 3: work out the number of moles of the reactant, using n=m/Mthen use the mole ratio of the equation to fill in the number of moles of the product:

 Equation Mg                  +                 2HCl                     à          MgCl2                      +                H2 Mass 192g This is the value you want to find Mr 24 2 n 8 à          1:1 mole ratio 8

Step 4: now you have the Mand number of moles of the product, rearrange n=m/Mto find the mass:
m=n x Mr

 Equation Mg                  +                 2HCl                     à          MgCl2                      +                H2 Mass 192g 16g Mr 24 2 n 8 à          1:1 mole ratio 8

Once you are familiar with the process, you don't need a calculation frame, but keep your workings well ordered and logical.

1. What mass of oxygen is needed to react with 8.5g of hydrogen sulphide (H2S)?

2H2S + 3O2 à 2SO2 + 2H2O

Find out how many moles of hydrogen sulphide there are, since you have its mass.
n=m/Mr
n=8.5/34=0.25

Mole ratio= 2:3 (2 moles of H2S : 3 moles of O2)
(0.25/2) x 3 = 0.375 --- 0.375 moles of O2 react with 0.25 moles of H2S, now you want to find the mass.

n=m/Mr
m= n x Mr
m= 0.375 x 32 = 12g

1. Railway lines are welded together by the thermite reaction, which produces molten iron. What mass of iron is formed from 1kg of iron oxide?

Fe2O3 + 2Al à 2Fe + Al2O3

n=m/Mr
n=1000g/160=6.25

Mole ratio= 1:2
6.25 x 2=12.5

m=n x Mr
m= 12.5 x 56 = 700g

Practice:
1. What mass of sodium hydroxide is formed when 46g of sodium reacts with excess water?
2. Calculate the mass of water formed when 32g of oxygen reacts with excess hydrogen.
3. Calcium carbonate thermally decomposes to form calcium oxide and carbon dioxide. If 44g of carbon dioxide are collected, what mass of calcium oxide is formed?

1.26 carry out mole calculations using volumes and molar concentrations
A solution contains a dissolved solute in a certain amount of solvent.
The concentration of a solution tells us how many moles of the solute are dissolved in one litre
(1 dm3) of the solvent.
The units for concentration are mol/dm3, and this is often shortened to M.
Concentration can also be measured in grams per litre.

n= v x c
Where v= volume (in dm3) and c= concentration (in mol/dm3)

NB: sometimes they give you the volume in cm3 so be careful, convert it to dm3 by dividing by 1000
(1 dm3 = 1000 cm3)

Or, you can just use: n= (v x c) / 1000

Remember to convert cm3 to dm3!

 Solution Formula Concentration (mol m-3) Concentration (g dm-3) Volume Number of moles Sodium hydroxide NaOH 1 500 cm3 Hydrochloric acid HCl 0.5 2 dm3 Sodium chloride NaCl 58.5 4 Potassium chloride KCl 200 cm3 0.2 Ammonium chloride NH4Cl 0.25 250 cm3 Silver nitrate AgNO3 2 0.5 Lithium iodide LiI Sulphuric acid H2SO4 0.2 1.8 Potassium nitrate KNO3 150 cm3 0.15

1. 25cm3 of a solution of 0.1M NaOH is neutralised by 50cm3 of HCl. What is the concentration of the HCl?

NaOH + HCl à NaCl + H2O

NB: remember to convert volumes to dm3!
n= v x c
n= 0.025 x 0.1=0.0025 mole

Mole ratio= 1:1, so moles of HCl= 0.0025 mole

C= n/v
C= 0.0025/ 0.05=0.05 mol/dm3

Practice:
1. What mass of silver chloride precipitate will be produced if 25 cmof 0.1M silver nitrate is added to excess sodium chloride solution?(Answer may not be exact, so you give it to 2 significant figures here because the most exact data they give you here is to 2 sig. fig. which is the volume.)
2. What mass of magnesium will react with 10cm3 of 1M HCl?   Extra: and what volume of hydrogen will be formed? (1 mole of any gas at RTP is 24dm3)

 Substance Formula Mr Mass of sample (g) Number of moles in sample (n=m/Mr) E.g. Water H2O 18 9 0.5 Carbon dioxide CO2 44 88 2 Ammonia NH3 17 1.7 0.1 Sulphur dioxide SO2 64 0.64 0.01 Sulphur trioxide SO3 80 80 1 Hydrogen bromide HBr 81 24.3 0.3 Sulphuric acid H2SO4 98 0.098 0.001 Nitric acid HNO3 63 3.15 0.05 Sodium nitrate NaNO3 85 21.25 0.25 Sodium carbonate Na2CO3 106 53 0.5

1. What mass of sodium hydroxide is formed when 46g of sodium reacts with excess water?

 2 Na + 2 H2O à 2 NaOH + H2 46g ? 1:1 ratio 23g : 40g 46g : 80g

2. Calculate the mass of water formed when 32g of oxygen reacts with excess hydrogen.

 2 H2 + O2 à 2 H2O 1 : 2 32g : 36g (m = n x Mr m = 2 x 18)

3. Calcium carbonate thermally decomposes to form calcium oxide and carbon dioxide. If 44g of carbon dioxide are collected, what mass of calcium oxide is formed?

 CaCO3 à CaO + CO2 1 : 1 56g : 44g *Remember that one mole of a substance is equivalent to its RFM in grams. For instance with CaO, the Mr of Ca is 40, and for O it is 16. Thus the RFM of CaO is 40 + 16 = 56. And since 44g of CO2 is 1 mole, then one mole of CaO must have been produced too (look at balanced equation), and 1 mole of CaO = 56g.

 Solution Formula Concentration (mol m-3) Concentration (g dm-3) Volume Number of moles Sodium hydroxide NaOH 1 40 500 cm3 0.5 Hydrochloric acid HCl 0.5 18.25 2 dm3 1 Sodium chloride NaCl 1 58.5 4 dm3 4 Potassium chloride KCl 1 74.5 200 cm3 0.2 Ammonium chloride NH4Cl 0.25 13.375 250 cm3 0.0625 Silver nitrate AgNO3 2 340 0.25 dm3 0.5 Lithium iodide LiI 1 134 1 dm3 1 Sulphuric acid H2SO4 0.2 19.6 9 dm3 1.8 Potassium nitrate KNO3 1 101 150 cm3 0.15

What mass of silver chloride precipitate will be produced if 25 cmof 0.1M silver nitrate is added to excess sodium chloride solution?(Answer may not be exact, so you give it to 2 significant figures here because the most exact data they give you here is to 2 sig. fig. which is the volume.)

 AgNO3 + NaCl à AgCl + NaNO3 1 : 1 Moles of AgNO3 = v x C = 0.025 x 0.1 = 0.0025 mol Moles of AgCl = 0.0025 mol Due to 1:1 ratio m = n x RFM = 0.0025 X 143.5 ≈ 0.36g (volume is only 2 sig. fig.)

2. What mass of magnesium will react with 10cm3 of 1M HCl?   Extra: and what volume of hydrogen will be formed? Assume RTP conditions -- 25°C and 1 atm (1 mole of any gas at RTP is 24dm3)

 Mg + 2 HCl à MgCl2 + H2 1 : 2 : 1 Moles of HCl = v x C = 0.01 x 1 = 0.01 moles Moles of Mg = 0.005 (due to 1:2 ratio, 0.01 moles of HCl will react with 0.005 moles of Mg) Mass of Mg = n x RFM = 0.005 x 24 = 0.12g 1 mole of H2 = 24 dm3 = 24,000 cm3 0.005 mole of H2 = 0.005 x 24,000 = 120 cm3

So that's done.. hope the answers help. And good luck with your IGCSEs! I really can't update like this anymore, apologies but this was just to complete this post. Hope it helps anyway. :)

Thank you to the anonymous person who spotted a mistake in one of my answers, please let me know when you do find some so I can change it! I won't do new posts but I can still change the existing ones if there's an error. :) ¡gracias

Plus , this blog is the best thing that happened to me during Christmas, Thanks very much

1. I don't think I actually put up answers but I can if you want them, do you still?
and hahahha, (y) nw, i'm glad :)

2. yess pleassssse

3. you should put answers also....
still, this blog is very good source of information...

2. THIS IS THE BEST THING THAT HAS HAPPENED TO BE EVER, YOU DESERVE TO BE CROWNED, I LOVE YOU, OMG

1. your nice comment is enough! :-)

3. This is so helpful for revision for GCSE's iv emailed it to my entire class, thank you!

1. you're welcome! and thanks for sharing my blog! :)

4. ilysm i want to caress your sweet face you saved my life can i dedicate a blog to you can i give you my firstborn can u have both of my kidneys will u marry me

6. this blog is
a m a z i n g.
thank you!

7. I was looking at the first answers table and
I'm not sure how the number of moles in the sample of sodium carbonate is 0.021?

I got m/Mr as 53/106.. so the answer was 0.5? :)

1. Ah yes you're right my bad! I forgot I changed some of the qs from my class exercise book to make the numbers easier, the mass in my book was 2.25g which gave 0.021..moles as an ans. (Didn't like the many decimal places so I changed the mass to 53, in which case yes the answer is 0.5 moles.)

Sorry! And well spotted, will change it now. :D

2. Ok, just checking - thank you!! :) And thank you for this blog in general.. it is literally getting me through science revision at the moment!!! :D

3. You're welcome :) Btw I thanked you at the bottom of the post haha (y) and good luck with your IGCSEs, I'm glad the blog helps! :D

8. how do you work out the mole ratio?! :s

1. You look at the balanced chemical equation. For instance with:
Mg + 2 HCl --> MgCl2 + H2
The ratio of Mg to HCl would be 1:2, since 1 mole of magnesium reacts with 2 moles of hydrochloric acid.

Does that make sense? :)

2. Wait, so why is it 1:1 in the example?

3. because that mole ratio is of Mg to H2, you're trying to find the mass of hydrogen so that is what's relevant in this example qs. :)

4. Ohhhhh! I get it! Thank you so much for answering! I finally get it :D

9. i want these type of ques to come in my exam
they r soooooo easy
I love this site

10. Can I say, though this is very helpful and your probably the best person for notes in IGCSE edexcel, what in the world makes you type so much and I think if thats a thing, I will be willing to pay a billion pounds for it.

1. Hahhahha I shall take that as a compliment? Back during IGCSEs this was for my own revision + to help others, since I got so many questions this was the best way to help everyone. It did take ages, but it paid off. :) And now other years can use it :D

11. this sucks

12. who ever published this example can suck my cock..this is all bullshit i got to know from my teacher..SON OF A BITCH..WHO EVER DID THIS!!!!!!!

1. REPENT!!!
YOU SINNER, "I AM COMING SOON." WITH A REWARD FOR YOUR WORTHLESS TALK.

13. Thankyou for uploading this... this is one of the most useful mole calculation site on the web! Thanks!

14. I would like to recommend your article on Sodium Hydro sulphide. For further information, you can refer Sodium Hydro sulphide

15. Is the Mr for HBr2 81 or 161? Because on the first table in the answers section, that is what it says for the hydrogen bromide row.

1. My apologies, it's meant to be 'HBr', I've changed it and the Mr would therefore be correct at 81. Thanks for spotting it. :)

16. SAVED MY LIFE

17. This was a great help. :D Thank you sooo much!!!

18. dont understand why '(due to 1:2 ratio, 0.01 moles of HCl will react with 0.005 moles of Mg)' works in the 2nd volumes question

19. can u put some more question for practice

20. This was very useful! thank you :)

21. amazing blog

22. why in Mg+2HCl in the end we are dividing 0.01 by 2 other then multiplying????????

23. thank you

24. thank you, it really helps... I like the way everything is explained

25. 0.005*24 does not equal 0.012g in the magnesium question. Correct mass should be 0.12

26. Thanks so much!!! It has helped me a lot....hope I get good marks in my exam tomorrow.. Thanks!

27. Sorry to bother you but I was just wondering for the first answers table, the answer for Sodium Bromide is different to what I got and I was really confused.
So Moles = Mass/Mr so therefore Moles = 24.3/81 which is = 0.3 but for your answer it was 0.22 so I was just wondering if I did something wrong...? Thank you for this Blog, it saved my life

1. Hi there, if you are referring to the Hydrogen Bromide answer then you are quite right! It's my bad. I'll change it, thanks for spotting that! And no problem, really glad the blog helps. :)

28. can u plssolve this 4 me

29. Thank You so much!!!! I never got this topic until i looked on this blog!! Its incredibly helpful!!!

30. Hi, the last question 2 just before the comments has the answer of 0.012 however it is actually 0.12. Just thought I should let you know :)

1. Thank you!! :)

2. WELCOME :)

31. guys
chill this topic is easy

32. YEET! ITS A GUD BLOG FAM!

33. My Chemistry exams are tomorrow, I’ve been trying to understand moles coz everything went bouncer, your blog helped me a lot, hoping I pass. Good luck for your blog, pretty sure I’ll check your blog when I have doubts. Gracias

34. You saved me sir as moles was a dreadful chapter like a bad dream for me but because of you I can score nice in moles in my mock examination

35. on topic 7 question number 2 where are you getting the other number of males

36. hi thank you for this but I have a question for the first practice question in the answer part

37. Hi!
Thank you so much for these! I'm preparing for IGCSEs and I was stuck on this topic.

Please tick a box showing your reaction, and any feedback is appreciated. :)

Note: This blog will no longer be updated as I finished IGCSEs in 2012. Sorry! :( If you are interested in buying IB notes though, please contact me. :)